9y^2-3y-2=0

Solution for 9y^2-3y-2=0 equation:

9y^2-3y-2=0

a = 9; b = -3; c = -2;
Δ = b2-4ac
Δ = -32-4·9·(-2)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-9}{2*9}=\frac{-6}{18}
=-1/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+9}{2*9}=\frac{12}{18}
=2/3
$